Optimali sutartis

Sutartis optimali, jei jos neapsimoka lauzyti.
Tegu sutartinis vektorius $(\bar{y_i}, \bar{x_i})$,
tada "apgavystes" vektorius

$$\begin{eqnarray}(\bar{\bar{y_i}}, \bar{\bar{x_i}})=\nonumber \\ \arg \max _{(y_... ...i,x_i, \bar{y_j}, \bar{x_j},\ j \neq i),\\ i=1,...,m. \nonumber \end{eqnarray}$$

Sutartis $x=(\bar{y_i}, \bar{x_i},\ i=1,...,m)$ optimali, kai

$$\begin{eqnarray}\min_x f(x)=0, \end{eqnarray}$$

kur

$$\begin{eqnarray}f(x)=\sum_{i=1}^m ((\bar{\bar{y_i}}-\bar{y_i})^2+( \bar{\bar{x_i}}-\bar{x_i})^2). \end{eqnarray}$$

$f(x)$ minimizuojama globaliu optimizavinmo metodu.